If $\frac{n}{4}-5=\frac{n}{6}+\frac{1}{2}$, find the value of $n$.

Given: $\frac{n}{4}-5=\frac{n}{6}+\frac{1}{2}$.

To do: To find the value of $n$.

Solution:
 

Given, $\frac{n}{4}-5=\frac{n}{6}+\frac{1}{2}$

$\Rightarrow \frac{n}{4}-\frac{n}{6}=5+\frac{1}{2}$

$\Rightarrow \frac{3n-2n}{12}=\frac{10+1}{2}$

$\Rightarrow \frac{n}{12}=\frac{11}{2}$

$\Rightarrow 2n=132$

$\Rightarrow n=\frac{132}{2}$

$\Rightarrow n=66$

Thus, $n=66$.

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Updated on: 10-Oct-2022

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