If $ \frac{5(1-x)+3(1+x)}{1-2 x}=8, $ then the value of $ x $ is_____.

Given:

\( \frac{5(1-x)+3(1+x)}{1-2 x}=8 \).
To do:

We have to find the value of $x$.

Solution:

$\frac{5(1-x)+3(1+x)}{1-2 x}=8$

$5(1-x)+3(1+x)=8\times(1-2x)$     (On cross multiplication)

$5-5x+3+3x=8-16x$

$8-2x=8-16x$

$16x-2x=8-8$

$14x=0$

$x=0$

Therefore, the value of $x$ is $0$.

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Updated on: 10-Oct-2022

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