If $\frac{3}{4}(x-1)=x-3$, find the value of $x$.
Given: $\frac{3}{4}(x-1)=x-3$.
To do: To find the value of $x$.
Solution:
$\frac{3}{4}(x-1)=x-3$
$\Rightarrow \frac{3}{4}x-\frac{3}{4}=x-3$
$\Rightarrow \frac{3}{4}x-x=\frac{3}{4}-3$
$\Rightarrow \frac{3x-4x}{4}=\frac{3-12}{4}$
$\Rightarrow \frac{-x}{4}=\frac{-9}{4}$
$\Rightarrow -x=-9$
$\Rightarrow x=9$
Thus, $x=9$.
Related Articles
- If \( x^{4}+\frac{1}{x^{4}}=119 \), find the value of \( x^{3}-\frac{1}{x^{3}} \).
- If $( \frac{( 3 x-4)^{3}-( x+1)^{3}}{( 3 x-4)^{3}+( x+1)^{3}}=\frac{61}{189})$, find the value of $x$.
- If \( x+\frac{1}{x}=5 \), find the value of \( x^{3}+\frac{1}{x^{3}} \).
- If \( x-\frac{1}{x}=7 \), find the value of \( x^{3}-\frac{1}{x^{3}} \).
- If \( x-\frac{1}{x}=5 \), find the value of \( x^{3}-\frac{1}{x^{3}} \).
- If \( x-\frac{1}{x}=3+2 \sqrt{2} \), find the value of \( x^{3}- \frac{1}{x^{3}} \).
- If \( x^{4}+\frac{1}{x^{4}}=194 \), find \( x^{3}+\frac{1}{x^{3}}, x^{2}+\frac{1}{x^{2}} \) and \( x+\frac{1}{x} \)
- If \( x+\frac{1}{x}=3 \), calculate \( x^{2}+\frac{1}{x^{2}}, x^{3}+\frac{1}{x^{3}} \) and \( x^{4}+\frac{1}{x^{4}} \).
- If \( x^{2}+\frac{1}{x^{2}}=98 \), find the value of \( x^{3}+\frac{1}{x^{3}} \).
- If \( x^{2}+\frac{1}{x^{2}}=51 \), find the value of \( x^{3}-\frac{1}{x^{3}} \).
- If \( x=2+\sqrt{3} \), find the value of \( x^{3}+\frac{1}{x^{3}} \).
- Find the value of $x^2+\frac{1}{x^2}$ if $x+\frac{1}{x}=3$.
- If $x - \frac{1}{x} = 3$, find the values of $x^2 + \frac{1}{x^2}$ and $x^4 + \frac{1}{x^4}$.
- Find the value of $x$$\frac{x+2}{2}- \frac{x+1}{5}=\frac{x-3}{4}-1$
- If $\frac{x}{4}=\frac{3}{6}$, find the value of $x$.
Kickstart Your Career
Get certified by completing the course
Get Started