If $\frac{1}{3}$ of a number is 4 more than its $\frac{1}{5}$ then what will be the number?

Given:If $\frac{1}{3}$ of a number is 4 more than its $\frac{1}{5}$ 

To do: Find the number.

Let the number be $y$.

$\frac{1}{3}$  of the number = $\frac{1}{3} \times$   $y = \frac{y}{3}$

 

$\frac{1}{5}$  of the number = $\frac{1}{5}\times  y = \frac{y}{5}$

Given that  $\frac{y}{3}$ =  $\frac{y}{5}$+ 4

Solving for y,   $\frac{y}{3} - \frac{y}{5} = \frac{5y - 3y}{15} = \frac{2y}{15}$ = 4

$y = 4 \times \frac{15}{2} = 30$

So the required number is 30

Verifying: $\frac{y}{3} = \frac{30}{3} =10; \frac{y}{5} = \frac{30}{5} = 6; 10 = 6 + 4 $True