If $\frac{1}{3}$ of a number is 4 more than its $\frac{1}{5}$ then what will be the number?
Given:If $\frac{1}{3}$ of a number is 4 more than its $\frac{1}{5}$
To do: Find the number.
Answer
Let the number be $y$.
$\frac{1}{3}$ of the number = $\frac{1}{3} \times$ $y = \frac{y}{3}$
$\frac{1}{5}$ of the number = $\frac{1}{5}\times y = \frac{y}{5}$
Given that $\frac{y}{3}$ = $\frac{y}{5}$+ 4
Solving for y, $\frac{y}{3} - \frac{y}{5} = \frac{5y - 3y}{15} = \frac{2y}{15}$ = 4
$y = 4 \times \frac{15}{2} = 30$
So the required number is 30
Verifying: $\frac{y}{3} = \frac{30}{3} =10; \frac{y}{5} = \frac{30}{5} = 6; 10 = 6 + 4 $True
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