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If $a+8\sqrt{5}b=8+(\frac{\sqrt{5}}{8})-\sqrt{5}+8-(\frac{\sqrt{5}}{8})+\sqrt{5}$, find a and b.
Given :
The given expression is, $a+8\sqrt{5}b=8+(\frac{\sqrt{5}}{8})-\sqrt{5}+8-(\frac{\sqrt{5}}{8})+\sqrt{5}$
To Find :
We have to find the values of a and b.
Solution :
$a+8\sqrt{5}b=8+(\frac{\sqrt{5}}{8})-\sqrt{5}+8-(\frac{\sqrt{5}}{8})+\sqrt{5}$
Rewrite the given expression,
$a+8\sqrt{5}b=8+8+(\frac{\sqrt{5}}{8})-(\frac{\sqrt{5}}{8})+\sqrt{5}-\sqrt{5}$
[$\sqrt{5}-\sqrt{5}=0$ ; $(\frac{\sqrt{5}}{8})-(\frac{\sqrt{5}}{8}) = 0$]
$a+8\sqrt{5}b=8+8$
$a+8\sqrt{5}b=16$
This can be written as,
$a+8\sqrt{5}b=16 + 8\sqrt{5} (0)$
Compare the values ,
a = 16
b = 0
Therefore, the values of a and b are 16, 0.
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