If a magnification of, −1 (minus one) is to be obtained by using a converging mirror, then the object has to be placed:

1. between pole and focus
2. at the centre of curvature
3. beyond the centre of curvature
4. at infinity

(b) at the centre of curvature

Explanation

Given:

Magnification, $m$ =$-$1

Here, magnification is with the positive sign $(-)$, which implies that the image is real and inverted.

$\because m=1\Rightarrow $ the size of the image is the same as that of the object.

In the case of the concave mirror, both of the above-mentioned conditions are only possible when the object is placed at the centre of curvature $(C)$ in front of the mirror.

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Updated on: 10-Oct-2022

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