If a = $\frac{7}{2}$ and b = $-\frac{5}{4}$
Find $\frac{a\ +\ b}{a\ -\ b}$.
Given: a = $\frac{7}{2}$ and b = $-\frac{5}{4}$
To find: Here we have to find the value of $\frac{a\ +\ b}{a\ -\ b}$, if a = $\frac{7}{2}$ and b = $-\frac{5}{4}$.
Solution:
a = $\frac{7}{2}$ and b = $-\frac{5}{4}$
Now,
$a\ +\ b\ =\ \frac{7}{2} \ +\ \left( -\ \frac{5}{4}\right)$
$a\ +\ b\ =\ \frac{7}{2} \ -\ \frac{5}{4}$
$a\ +\ b\ =\ \frac{14\ -\ 5}{4}$
$a\ +\ b\ =\ \mathbf{\frac{9}{4}}$
Also,
$a\ -\ b\ =\ \frac{7}{2} \ -\ \left( -\ \frac{5}{4}\right)$
$a\ -\ b\ =\ \frac{7}{2} \ +\ \frac{5}{4}$
$a\ -\ b\ =\ \frac{14\ +\ 5}{4}$
$a\ -\ b\ =\ \mathbf{\frac{19}{4}}$
So,
$\frac{a\ +\ b}{a\ -\ b}$
$=\ \frac{\frac{9}{4}}{\frac{19}{4}}$
$=\ \frac{9}{4} \ \times \ \frac{4}{19}$
$=\ \mathbf{\frac{9}{19}}$
So, value of $\frac{a\ +\ b}{a\ -\ b}$, if a = $\frac{7}{2}$ and b = $-\frac{5}{4}$ is $\frac{9}{19}$.
Related Articles
- If $\frac{7+\sqrt{5}}{7-\sqrt{5}}=a+b \sqrt{5}$, find a and b.
- Find:(i) $\frac{1}{4}$ of (a) $\frac{1}{4}$(b) $\frac{3}{5}$ (c) $\frac{4}{3}$(ii) $\frac{1}{7}$ of (a) $\frac{2}{9}$ (b) $\frac{6}{5}$ (c) $\frac{3}{10}$
- Add the following algebraic expressions(i) \( 3 a^{2} b,-4 a^{2} b, 9 a^{2} b \)(ii) \( \frac{2}{3} a, \frac{3}{5} a,-\frac{6}{5} a \)(iii) \( 4 x y^{2}-7 x^{2} y, 12 x^{2} y-6 x y^{2},-3 x^{2} y+5 x y^{2} \)(iv) \( \frac{3}{2} a-\frac{5}{4} b+\frac{2}{5} c, \frac{2}{3} a-\frac{7}{2} b+\frac{7}{2} c, \frac{5}{3} a+ \) \( \frac{5}{2} b-\frac{5}{4} c \)(v) \( \frac{11}{2} x y+\frac{12}{5} y+\frac{13}{7} x,-\frac{11}{2} y-\frac{12}{5} x-\frac{13}{7} x y \)(vi) \( \frac{7}{2} x^{3}-\frac{1}{2} x^{2}+\frac{5}{3}, \frac{3}{2} x^{3}+\frac{7}{4} x^{2}-x+\frac{1}{3} \) \( \frac{3}{2} x^{2}-\frac{5}{2} x-2 \)
- If $\frac{1}{b} \div \frac{b}{a} = \frac{a^2}{b}$, where a, b not equal to 0, then find the value of $\frac{\frac{a}{(\frac{1}{b})} - 1}{\frac{a}{b}}$.
- Take away:(i) \( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+ \) \( \frac{3}{5} x+\frac{1}{4} \)(ii) \( \frac{5 a^{2}}{2}+\frac{3 a^{3}}{2}+\frac{a}{3}-\frac{6}{5} \) from \( \frac{1}{3} a^{3}-\frac{3}{4} a^{2}- \) \( \frac{5}{2} \)(iii) \( \frac{7}{4} x^{3}+\frac{3}{5} x^{2}+\frac{1}{2} x+\frac{9}{2} \) from \( \frac{7}{2}-\frac{x}{3}- \) \( \frac{x^{2}}{5} \)(iv) \( \frac{y^{3}}{3}+\frac{7}{3} y^{2}+\frac{1}{2} y+\frac{1}{2} \) from \( \frac{1}{3}-\frac{5}{3} y^{2} \)(v) \( \frac{2}{3} a c-\frac{5}{7} a b+\frac{2}{3} b c \) from \( \frac{3}{2} a b-\frac{7}{4} a c- \) \( \frac{5}{6} b c \)
- Find the following product.\( \left(\frac{-2}{7} a^{4}\right) \times\left(\frac{-3}{4} a^{2} b\right) \times\left(\frac{-14}{5} b^{2}\right) \)
- Find the sum:\( \frac{a-b}{a+b}+\frac{3 a-2 b}{a+b}+\frac{5 a-3 b}{a+b}+\ldots \) to 11 terms.
- i)a) $\frac{1}{4} of \frac{1}{4}$b) $\frac{1}{4} of \frac{3}{5} $c) $\frac{1}{4} of \frac{4}{3} $ii) a) $\frac{1}{ 7} of \frac{2}{ 9}$b) $\frac{1}{ 7} of \frac{6}{5}$c) $\frac{1}{ 7} of \frac{3}{10}$
- If a and b are different positive primes such that\( \left(\frac{a^{-1} b^{2}}{a^{2} b^{-4}}\right)^{7} \p\left(\frac{a^{3} b^{-5}}{a^{-2} b^{3}}\right)=a^{x} b^{y} \), find \( x \) and \( y . \)
- Multiply:\( \left(\frac{-a}{7}+\frac{a^{2}}{9}\right) \) by \( \left(\frac{b}{2}-\frac{b^{2}}{3}\right) \)
-  Find $\frac{2}{7}\times\frac{5}{9}$ a) Is $\frac{2}{7}\times\frac{5}{9}$= $\frac{5}{9}\times\frac{2}{7}$ b) Is $\frac{2}{7}\times\frac{5}{9}$ > or$\frac{5}{9}\times\frac{2}{7}$?
- Draw number lines and locate the points on them:(a) \( \frac{1}{2}, \frac{1}{4}, \frac{3}{4}, \frac{4}{4} \)(b) \( \frac{1}{8}, \frac{2}{8}, \frac{3}{8}, \frac{7}{8} \)(c) \( \frac{2}{5}, \frac{3}{5}, \frac{8}{5}, \frac{4}{5} \)
- Given that $sin\ \theta = \frac{a}{b}$, then $cos\ \theta$ is equal to(A) \( \frac{b}{\sqrt{b^{2}-a^{2}}} \)(B) \( \frac{b}{a} \)(C) \( \frac{\sqrt{b^{2}-a^{2}}}{b} \)(D) \( \frac{a}{\sqrt{b^{2}-a^{2}}} \)
- Subtract:(i) $-5xy$ from $12xy$(ii) $2a^2$ from $-7a^2$(iii) \( 2 a-b \) from \( 3 a-5 b \)(iv) \( 2 x^{3}-4 x^{2}+3 x+5 \) from \( 4 x^{3}+x^{2}+x+6 \)(v) \( \frac{2}{3} y^{3}-\frac{2}{7} y^{2}-5 \) from \( \frac{1}{3} y^{3}+\frac{5}{7} y^{2}+y-2 \)(vi) \( \frac{3}{2} x-\frac{5}{4} y-\frac{7}{2} z \) from \( \frac{2}{3} x+\frac{3}{2} y-\frac{4}{3} z \)(vii) \( x^{2} y-\frac{4}{5} x y^{2}+\frac{4}{3} x y \) from \( \frac{2}{3} x^{2} y+\frac{3}{2} x y^{2}- \) \( \frac{1}{3} x y \)(viii) \( \frac{a b}{7}-\frac{35}{3} b c+\frac{6}{5} a c \) from \( \frac{3}{5} b c-\frac{4}{5} a c \)
- Find acute angles \( A \) and \( B \), if \( \sin (A+2 B)=\frac{\sqrt{3}}{2} \) and \( \cos (A+4 B)=0, A>B \).
Kickstart Your Career
Get certified by completing the course
Get Started