If $(2x-1,3y+1)$ and $(x+3,y-4)$ are equal ordered pairs. Find the values of $x$ and $y$.

Given:

$(2x-1,3y+1)$ and $(x+3,y-4)$ are equal ordered pairs.

To do:

We have to find the values of $x$ and $y$.

Solution:

We know that,

Two ordered pairs are equal if and only if the corresponding first components are equal and the second components are equal. 

Therefore,

$2x-1 = x+3$ and $3y+1 = y-4$

$2x-x=3+1$ and $3y-y=-4-1$

$x=4$ and $2y=-5$

$x=4$ and $y=\frac{-5}{2}$

The values of $x$ and $y$ are $4$ and $\frac{-5}{2}$ respectively.