If 2 is a zero of the polynomial $p(x)= 4x^2+2x-5a$, then find the value of a.

Given :

The given polynomial is $p(x)= 4x^2+2x-5a$.

2 is the zero of the polynomial $p(x)= 4x^2+2x-5a$.

To find :

We have to find the value of a.

Solution :

The zero of the polynomial is defined as any real value of x, for which the value of the polynomial becomes zero.

Therefore,

Zero of the polynomial $p(2)= 4(2)^2+2(2)-5a=0$

$4(4)+4-5a=0$

$5a=16+4$

$5a=20$

$a=\frac{20}{5}$

$a=4$

The value of a is 4.

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Updated on: 10-Oct-2022

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