Identify the substances that are oxidised and the substances which are reduced in the following reactions.
(i) 4Na(s) + O2(g) → 2Na2O(s)
(ii) CuO (s) + H2(g) → Cu (s) + H2O(l)


(a) $4Na (s) + O_2 (g) → 2Na_2O (s)$ : In the given equation, Sodium (Na) is oxidised as it gains oxygen and oxygen gets reduced. 
         
(b)  $CuO (s) + H_2 (g) → Cu (s) + H_2O (l)$ : In the given equation, Copper oxide (CuO) is reduced to copper (Cu) while hydrogen (H2) gets oxidised to water (H2O).

Tutorialspoint
Tutorialspoint

Simply Easy Learning

Updated on: 14-Mar-2023

165 Views

Kickstart Your Career

Get certified by completing the course

Get Started
Advertisements