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(i) Express 49 as the sum of 7 odd numbers.
(ii) Express 121 as the sum of 11 odd numbers.
Given:
(i) 49
(ii) 121
To do:
We have to express 49 as the sum of 7 odd numbers and 121 as the sum of 11 odd numbers.
Solution:
$49=7^2$
This implies,
$1 + 3 + 5 + 7 + 9 + 11 + 13 = 49
$121=11^2$
This implies,
$1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 = 121$
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