How much $x^3 - 2x^2 + x + 4$ is greater than $2x^3 + 7x^2 -5x + 6$

Given:  $x^3 - 2x^2 + x + 4$ and $2x^3 + 7x^2 -5x + 6$

To find : We have to find by how  much $x^3 - 2x^2 + x + 4$ is greater than $2x^3 + 7x^2 -5x + 6$

Solution:

We will know how much $x^3- 2x^2 + x + 4$ is greater than $2x^3+ 7x^2 -5x + 6$ by subtracting $2x^3 + 7x^2 -5x + 6$ from $x^3 - 2x^2 + x + 4$.

$x^3 - 2x^2 + x + 4  - (2x^3 + 7x^2 -5x + 6)$

=$ x^3 - 2x^2 + x + 4 - 2x^3 - 7x^2 + 5x - 6$

= $- x^3 - 9x^2 + 6x -2$  

By this much first expression greater than the second expression

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Updated on: 10-Oct-2022

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