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How many terms are there in the A.P. ?$7, 13, 19, …, 205$.
Given:
Given A.P. is $7, 13, 19, …, 205$.
To do:
We have to find the number of terms in the given A.P.
Solution:
Here,
$a_1=7, a_2=13, a_3=19$
Common difference $d=a_2-a_1=13-7=6$
Let $205$ be the nth term.
We know that,
nth term $a_n=a+(n-1)d$
Therefore,
$a_{n}=7+(n-1)(6)$
$205=7+n(6)-1(6)$
$205-7=6n-6$
$198+6=6n$
$6n=204$
$n=\frac{204}{6}$
$n=34$
Hence, there are 34 terms in the given A.P.    
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