- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Half the perimeter of a garden whose length is 4 m more than its width is 36 m. Find the dimensions of the garden.
Given :
Half the perimeter of a garden whose length is 4 m more than its width is 36 m.
To do:
We have to find the dimensions of the garden.
Solution :
Perimeter of a rectangle of length $l$ and breadth $b = 2 (l + b)$.
Let the length of the rectangle be $l$ and the width of the rectangle be $b$.
Therefore,
Half the perimeter of rectangle $=\frac{2\ ( l\ +\ b)}{2}$
Half the perimeter of rectangle $=l+b$.
Given that half the perimeter of the rectangular garden $= 36\ m$.
$l+b=36\ m$......(i)
It is given that, length of the rectangular garden is 4 m more than its width.
This implies,
$l = b + 4$.......(ii)
Substituting (ii) in (i), we get,
$b + 4 + b = 36$
$2b = 36 - 4$
$2b = 32$
$b =\frac{32}{2}$
$b = 16\ m$
Substitute $b = 16$ in (ii)
$l = 16 + 4$
$l = 20\ m$
Therefore, the length of the rectangular garden is $20\ m$ and the width of the rectangular garden is $16\ m$.