Half of a herd of a deer are grazing in the field and three fourth of the remaining are playing nearby the rest 9 are drinking water from a pond. Find the number of deer in the herd.
Given: Half of a herd of a deer are grazing in the field and three fourth of the remaining are playing nearby the rest 9 are drinking water from a pond.
To do: To find the number of deer in the herd.
Solution:
Let total no. of deer $=x$
Half of herd $=\frac{x}{2}$
$\frac{3}{4}$ of remaining half herd $=( \frac{x}{2})( \frac{3}{4})=\frac{3x}{8}$
$\therefore$ Remaining deer $=9$
$\Rightarrow x=( \frac{x}{2})+( \frac{3x}{8})+9$
$\Rightarrow x=\frac{( 4x+3x+72)}{8}$
$\Rightarrow 8x=7x+72$
$\Rightarrow 8x-7x=72$
$\Rightarrow x=72$
$\therefore$ Total no. of deer are $72$.
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