Given $sin\alpha=\frac{\sqrt{3}}{2}$ and $cos\beta=0$, then find the value of $( \beta-\alpha)$.
Given: $sin\alpha=\frac{\sqrt{3}}{2}$ and $cos\beta=0$.
To do: To find the value of $( \beta-\alpha)$.
Solution:
As given,
$sin\alpha=\frac{\sqrt{3}}{2}$
$\Rightarrow \alpha=60^o$
And $cos\beta=0$
$\Rightarrow \beta=90^o$
$\therefore \beta-\alpha=90^o-60^o$
$\Rightarrow \beta-\alpha=30^o$
Thus, the value of $( \beta-\alpha)$ is $30^o$.
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