1. $y = x$
  2. $x + y = 0$
  3. $y = 2x$
  4. $2 + 3y = 7x$
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From the choices given below, choose the equation whose graph is given in figure.

  1. $y = x$
  2. $x + y = 0$
  3. $y = 2x$
  4. $2 + 3y = 7x$
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To do: 

We have to find the equation whose graph is given in the figure.

Solution:

Let us substitute the given points in each of the equations in the options.

The given points should satisfy the equation whose graph is given in the figure.

Therefore,

(i) $(-1, 1)$

$y=x$

$1≠-1$

(ii) $(-1, 1)$

$x+y=0$

$-1+1=0$

$(1, -1)$

$x+y=0$

$1+(-1)=1-1=0$

Therefore, $(-1, 1)$ and $(1, -1)$ satisfy the equation $x+y=0$.

(iii) $(-1, 1)$

$y=2x$

$1≠2(-1)$

(iv) $(-1, 1)$

$2+3y=7x$

$2+3(1)=2+3$

$=5$

$≠7(-1)$

Hence, the equation whose graph is given in the figure is $x+y=0$.

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Updated on: 10-Oct-2022

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