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From a solid cylinder of height 2.8 cm and diameter 4.2 cm a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid. [Take $\pi =\frac{22}{7}$]
Given: Height of the cylinder$=2.8\ cm$, diameter$=4.2\ cm$.
To do: To find the total surface area of the remaining soloids.
Solution:
The following figure shows the required cylinder and the conical cavity
Given Height (b) of the conical Part = Height (h) of the cylindrical part = 2.8 cm
Diameter of the cylindrical part = Diameter of the conical part = 42 cm .
Radius of the cylindrical part = Radius of the conical part=21 cm
Slant height (of the conical part
Total surface area of the remaining solid = Curved surface area of the cylindrical part +Curved surface area of the conical part + Area of the cylindrical base
Thus, the total surface area of the remaining solid is 73.92 cm
Updated on: 10-Oct-2022
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