From a rope of 10 meters long, two pieces of lengths $\frac{13}{5}$ m and $\frac{33}{10}$ m are cut off. What is the length of the remaining rope?
Given:
Total length of the rope $=10\ m$.
Two pieces of lengths $\frac{13}{5}$ m and $\frac{33}{10}$ m are cut off.
To do:
We have to find the length of the remaining rope.
Solution:
Total length of pieces that are cut off $=\frac{13}{5}+\frac{33}{10}\ m$
$=\frac{13\times2+33}{10}\ m$
$=\frac{26+33}{10}\ m$
$=\frac{59}{10}\ m$
Length of the rope remaining $=$ Total length of the rope $-$ Total length of pieces that are cut off
$=10-\frac{59}{10}\ m$
$=\frac{10\times10-59}{10}\ m$
$=\frac{100-59}{10}\ m$
$=\frac{41}{10}\ m$.
The length of the remaining rope is $\frac{41}{10}\ m$.
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