$\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$

Given: $\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$

To find: We have to find the value of  $\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$

Solution: 

$\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$

$Taking\ \frac{7}{9} \ common,\ we\ get\ that$

$=\ \frac{7}{9} \times \ \left(\frac{-1}{2} \ -\ \left(\frac{-3}{2}\right)\right)$

$=\ \frac{7}{9} \times \ \left(\frac{-1}{2} \ +\ \frac{3}{2}\right)(( -\ \times \ -) \ =\ +)$

$=\ \frac{7}{9} \times \ \left(\frac{3-1}{2}\right)$

$=\ \frac{7}{9} \times \ \left(\frac{2}{2}\right) \ =\ \frac{7}{9} \times \ 1$

$=\ \frac{7}{9}$

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Updated on: 10-Oct-2022

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