For which values of  '$a$'  and ' $b$ '  does the following pair of linear equations an infinite number of solutions $2x+3y=7,(a-b)x+(a+b)y=3a+b-2$.


Given: The following pair of linear equations an infinite number of solutions $2x+3y=7,(a-b)x+(a+b)y=3a+b-2$.

To do: To find the value of $a$ and $b$.

Solution:

Given equations are: $2x+3y=7$   ..... $( i)$

$( a-b)x+( a+b)y=3a+b-2$  ...... $( ii)$

As gievn, It has infinitely many solutions

Therefore, $\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$

$\Rightarrow \frac{2}{a-b}=\frac{3}{a+b}=\frac{7}{3a+b-2}$

$\frac{2}{a-b}=\frac{3}{a+b}$

$\Rightarrow 2( a+b)=3( a-b)$

$\Rightarrow 2a+2b=3a-3b$

$\Rightarrow a-5b=0$

$\Rightarrow a=5b$ ..... $( iii)$
 
Now, $\frac{3}{a+b}=\frac{7}{3a+b-2}$

$\Rightarrow 7a+7b=9a+3b-6$

$\Rightarrow 2a-4b=6$

$\Rightarrow a-2b=3$

$\Rightarrow 5b-2b=3$

$\Rightarrow 3b=3$

$\Rightarrow b=1$

$\therefore a=5\times1=5$      [$\because a=5b$ from $( iii)$]

Thus, $a=5$ and $b=1$.

Updated on: 10-Oct-2022

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