For what value of $k$, the pair of linear equations $2kx+5y=7,6x-5y=11$ has a unique solution.


Given: The pair of linear equations $2kx+5y=7,\ 6x-5y=11$ has a unique solution.

To do: To find the value of $k$ for unique solution.

Solution:

The equation are:

$2kx+5y-7=0$

$6x-5y-11=0$

Here, $a_1=2k,\ b_1=5,\ c_1=-7$

And $a_2=6,\ b_2=-5,\ c_2=-11$

For the system to have unique solution

$\Rightarrow \frac{a_1}{a_2}\
eq\frac{b_1}{b_2}$
$\Rightarrow \frac{2k}{6}\
eq\frac{5}{-5}$
$\Rightarrow 2k\
eq-\frac{6\times5}{5}$

$\Rightarrow 2k\
eq-6$

$\Rightarrow k\
eq-\frac{6}{2}=-3$ 

Thus, for $k\
eq-3$ the given system of equations have unique solution.

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Updated on: 10-Oct-2022

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