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For what value of $k$, the pair of linear equations $2kx+5y=7,6x-5y=11$ has a unique solution.
Given: The pair of linear equations $2kx+5y=7,\ 6x-5y=11$ has a unique solution.
To do: To find the value of $k$ for unique solution.
Solution:
The equation are:
$2kx+5y-7=0$
$6x-5y-11=0$
Here, $a_1=2k,\ b_1=5,\ c_1=-7$
And $a_2=6,\ b_2=-5,\ c_2=-11$
For the system to have unique solution
$\Rightarrow \frac{a_1}{a_2}\
eq\frac{b_1}{b_2}$
eq\frac{b_1}{b_2}$
$\Rightarrow \frac{2k}{6}\
eq\frac{5}{-5}$
eq\frac{5}{-5}$
$\Rightarrow 2k\
eq-\frac{6\times5}{5}$
eq-\frac{6\times5}{5}$
$\Rightarrow 2k\
eq-6$
eq-6$
$\Rightarrow k\
eq-\frac{6}{2}=-3$
eq-\frac{6}{2}=-3$
Thus, for $k\
eq-3$ the given system of equations have unique solution.
eq-3$ the given system of equations have unique solution.
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