Find two consecutive natural numbers whose product is 20.

Given:

Product of two consecutive natural numbers is 20.

 To do:

We have to find the numbers.

Solution:

Let the two consecutive natural numbers be $x$ and $x+1$.

According to the question,

$x(x+1)=20$

$x^2+x=20$

$x^2+x-20=0$

Solving for $x$ by factorization method, we get,

$x^2+x-20=0$

$x^2+5x-4x-20=0$

$x(x+5)-4(x+5)=0$

$(x-4)(x+5)=0$

$x-4=0$ or $x+5=0$

$x=4$ or $x=-5$

$-5$ is not a natural number.

Therefore, the two consecutive natural numbers whose product is 20 are $4$ and $4+1=5$.

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Updated on: 10-Oct-2022

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