Find three consecutive even numbers such that sum of 1st and last numbers exceed the second number by 10.

To do: Find three consecutive even numbers such that sum of 1st and last numbers exceed the second number by 10.

Solution:

Let the numbers be $a, a +2 \ and \ a + 4$

According to question, sum of $a$ and $a+ 4$ exceeds $a+2$ by 10

$a + a + 4 = a + 2 + 10$

=> $2a + 4 = a + 12$

=> $2a - a = 12 - 4$

=>$ a = 8$

Therefore,

First number = $8$

Second number = $8+2 = 10$

Third number is $a+4 = 12$

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Updated on: 10-Oct-2022

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