Find the zeroes of polynomial: $q( x)=\sqrt{3}x^2+10x+7\sqrt{3}$.
Given: Polynomial: $q( x)=\sqrt{3}x^2+10x+7\sqrt{3}$.
To do: To find the zeroes of $q( x)=\sqrt{3}x^2+10x+7\sqrt{3}$.
Solution:
As given, $q( x)=\sqrt{3}x^2+10x+7\sqrt{3}$
We put $q( x)=0$
$\Rightarrow \sqrt{3}x^2+10x+7\sqrt{3} = 0$
$\Rightarrow \sqrt{3}x^2+3x+7x+7\sqrt{3}x = 0$
$\Rightarrow \sqrt{3}x(x+\sqrt{3})+7 (x+\sqrt{3}) = 0$
$\Rightarrow ( x+\sqrt{3})( \sqrt{3}x+7) = 0$
Thus, $x=-\sqrt{3}$ and $x=-7/\sqrt{3}$
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