Find the volume of a cube, one face of which has an area of $64\ m^2$.

Given :

Area of the face of a cube $=64\ m^2$.

To do :

We have to find the volume of the cube.

Solution :

Let the side of the cube be $s$ m.

Area of the face of a cube $= s^2$ sq. m.

$64\ m^2 = s^2\ m^2$

$8 \times 8=  s^2$

$s = 8\ m$.

The volume of a cube of side $s = s^3\ m^3$.

The volume of the given cube $= (8)^3\ m^3$

$= 512\ m^3$

Therefore, the volume of the cube is $512\ m^3$.

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Updated on: 10-Oct-2022

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