Find the value using suitable identity$( x-y^2 )^2$

Given:

$(x-y^2)^2$

To do:

We have to find the value of $(x-y^2)^2$ using a suitable identity.

Solution:

We know that,

$(a-b)^2=a^2-2ab+b^2$

Therefore,

$(x-y^2)^2=(x)^2-2\times x \times y^2 +(y^2)^2$

$=x^2-2xy^2+y^4$.