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Find the value using suitable identity$( x-y^2 )^2$
Given:
$(x-y^2)^2$
To do:
We have to find the value of $(x-y^2)^2$ using a suitable identity.
Solution:
We know that,
$(a-b)^2=a^2-2ab+b^2$
Therefore,
$(x-y^2)^2=(x)^2-2\times x \times y^2 +(y^2)^2$
$=x^2-2xy^2+y^4$.
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