Find the value Of $x$ $ \frac{1}{2}-\frac{1}{3}(x-1)+2=0 $

Given: $ \frac{1}{2}-\frac{1}{3}(x-1)+2=0 $

To do: Find $x$.

Solution:

$ \frac{1}{2}-\frac{1}{3}(x-1)+2=0 $

$ \frac{1}{2}-\frac{1}{3}x +\frac{1}{3}+2=0$

$\frac{1}{2}+\frac{1}{3}+2=\frac{1}{3}x$

LCM of 2 and 3  is 6

$\frac{3+2+6}{6}=\frac{1}{3}x$

$\frac{11}{6}=\frac{1}{3}x$

Cross multiplying 3 to LHS

$3\frac{11}{6}=x$

$\frac{11}{2}=x$

Therefore, the value of $x$ is $\frac{11}{2}$

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Updated on: 10-Oct-2022

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