Find the value of x:
$\frac{x\ -\ 5}{2} \ +\ \frac{2}{5} \ -\ \frac{2x}{7} \ =\ 1$
Given: $\frac{x\ -\ 5}{2} \ +\ \frac{2}{5} \ -\ \frac{2x}{7} \ =\ 1$
To find: Here we have to find the value of x in the given expression.
Solution:
$\frac{x\ -\ 5}{2} \ +\ \frac{2}{5} \ -\ \frac{2x}{7} \ =\ 1$
$\frac{x\ -\ 5}{2} \ -\ \frac{2x}{7} \ =\ 1\ -\ \frac{2}{5}$
$\frac{7( x\ -\ 5) \ -\ 2( 2x)}{14} \ =\ \frac{5\ -\ 2}{5}$
$\frac{7x\ -\ 35\ -\ 4x}{14} \ =\ \frac{3}{5}$
$\frac{3x\ -\ 35}{14} \ =\ \frac{3}{5}$
$3x\ -\ 35\ =\ \frac{3\ \times \ 14}{5}$
$3x\ -\ 35\ =\ \frac{42}{5}$
$3x\ =\ \frac{42}{5} \ +\ 35$
$3x\ =\ \frac{42\ +\ 175}{5}$
$3x\ =\ \frac{217}{5}$
$x\ =\ \frac{217}{5\ \times \ 3}$
$\mathbf{x\ =\ \frac{217}{15}}$
So, value of x is $\frac{217}{15}$.
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