Find the value of $ x $ in the given figure.
"

Given:

In the given figure, $(2x+60)^o$ and $(3x-40)^o$ form a linear pair.

To do:

We have to find the value of $x$. 

Solution:

We know that,

Sum of the angles in a linear pair is $180^o$.

$(2x+60)^o+(3x-40)^o=180^o$

$5x+20^o=180^o$

$5x=180^o-20^o$

$5x=160^o$

$x=\frac{160^o}{5}$

$x=32^o$

The value of $x$ is $32^o$.

Tutorialspoint

e

Updated on: 10-Oct-2022

34 Views

Kickstart Your Career

Get certified by completing the course

Get Started