Find the value of $x$ if $(3^{x+2}-9)\div 8 = 9$

Given : $\left( 3^{x+2} -9\right) \div 8\ =\ 9$$(3^{x+2}-9)\div 8 = 9$

To do: We have to find $x$

Solution:

$\left( 3^{x+2} -9\right) \div 8\ =\ 9$

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$(3^{x+2}-9)\div 8 = 9$

$\frac{3^{x+2}-9}{8}=9$

$3^{x+2}-9=9\times8$

$3^{x+2}=72+9$

$3^x\times3^2=81$

$3^x\times9=81$

$3^x=\frac{81}{9}$

$3^x=9$

$3^2=3^2$

Therefore the value of $x \ is \ 2$