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Find the value of the following expressions, when $x=-1$
$(i)$. $2x-7$
$(ii)$. $-x+2$
$(iii)$. $x^2+2x+ 1$
$(iv)$. $2x^2-x-2$
Given:
$(i)$. $2x-7$
$(ii)$. $-x+2$
$(iii)$. $x^2+2x+ 1$
$(iv)$. $2x^2-x-2$
Solution:
$(i)$. $2x-1$
$=2\times\ (-1)-7$
$=-9$
$(ii)$. $-x+2$
$=-(-1)+2$
$=1+2$
$=3$
$(iii)$. $x^2+2x+1$
$=(-1)\ \times\ (-1)+2\ \times\ (-1)+1$
$=1-2+1$
$=0$
$(iv)$. $2x^2-x-2$
$=2(-1)\ \times\ (-1)-(-1)-2$
$=2+1-2=1$
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