Find the value of t$\frac{3t-2}{4}$$- $$\frac{2t+3}{3}$ = $\frac{2}{3-t}$

Academic Mathematics NCERT Class 8

Given:

$\frac{3t-2}{4}$- $\frac{2t+3}{3}$ = $\frac{2}{3-t}$

To find: We have to find the value of t.

Solution:

$\frac{3t-2}{4}$- $\frac{2t+3}{3}$ = $\frac{2}{3-t}$

The LCM of 3 and 4 is 12. Therefore,

=> $\frac{9t - 6 -8t -12}{12} = $$\frac{2-3t}{3}$

=> $\frac{t-18}{4}$= $2 - 3t$

=> $t - 18 = 8 - 12t$

=> $13t = 8 + 18 = 26$

=> $t = \frac{26}{13}$

Therefore, the value of t = $\frac{26}{13}$

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Updated on: 10-Oct-2022

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