Find the value of t, if $0.1(t-3)=0.15(t-4)$​.


Given:

$0.1(t-3) =0.15(t-4)$

To do:


We have to find the value of t.

Solution:

$0.1(t-3) =0.15(t-4)$

$0.1(t) - 0.1(3) = 0.15(t) - 0.15(4)$

$0.1t - 0.3 = 0.15t - 0.6$

$(0.15-0.1)t=0.6-0.3$

$0.05t = 0.3$

$t = \frac{0.3}{0.05}$

$t = \frac{30}{5}$

$t= 6$

The value of t is 6.


Updated on: 10-Oct-2022

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