Find the value of:
$\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$

Given: $\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$.

To find: Here we have to find the value of the given expression  $\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$.

Solution:

$\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$

$=\ \left( 1\ +\ \frac{1}{4}\right) \ \times \ 4$

$=\ \left(\frac{4\ +\ 1}{4}\right) \ \times \ 4$

$=\ \left(\frac{5}{4}\right) \ \times \ 4$

$=\ \mathbf{5}$

So, the answer is 5.

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Updated on: 10-Oct-2022

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