Find the value of $p$ for the following distribution whose mean is 16.6.
$x$:81215$p$202530
$f$:121620241684.


Given:

The mean of the given data is 16.6.

To do:

We have to find the value of $p$.

Solution:

$x$$f$$f \times\ x$
81296
1216192
1520300
$p$24$24p$
2016320
258200
304120
Total100$1228+24p$

We know that, 

Mean$=\frac{\sum fx}{\sum f}$

Therefore,

Mean $16.6=\frac{1228+24p}{100}$

$16.6(100)=1228+24p$

$1660=1228+24p$

$24p=1660-1228$

$p=\frac{432}{24}$

$p=18$

The value of $p$ is $18$.

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Updated on: 10-Oct-2022

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