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Find the value of n:$4^{2n} \times 4^n = 2^{12}$
Given :
The given expression is $4^{2n} \times 4^n = 2^{12}$.
To do :
We have to find the value of n.
Solution :
$4^{2n} \times 4^n = 2^{12}$
We know that,
$a^m \times a^n= a^{m+n}$
$2^{12}$ can be written as,
$2^{12}= (2^2)^6 = 4^6$
$4^{2n}\times 4^n = 2^{12}$
$4^{2n}\times 4^n =4^6$
$(4)^{2n+n}= 4^6$
Comparing the powers on both sides, we get,
$2n+n = 6$
$3n = 6$
$n = \frac{6}{3}$
$n = 2$.
The value of n is 2.
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