Find the value of k in the problem given belowArea of the triangle formed by points(k,0).(-1.2)and (4,3)is 12units2 then find k
Answer
Area of a triangle with vertices (x1,y1), (x2,y2), (x3,y3) is given by the following formula
A = ($\frac{1}{2}$) [x1 (y2 – y3 ) + x2 (y3 – y1 ) + x3(y1 – y2)]
Given vertices as (k,0), (-1, 2), (4,3) and area = 12 sq units. To find k
A = $\frac{1}{2}$[k(2-3) -1(3-0) + 4(0-2)] = 12
=$\frac{1}{2}$[-k -3-8] = 12
-k -11 = 12x2 = 24
k = -24 - 11 = -35
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