Find the value of $a$ if $ 2-3 a+7=8 a+3-a $.
Given:
\( 2-3 a+7=8 a+3-a \).
To do:
We have to find the value of $a$.
Solution:
\( 2-3 a+7=8 a+3-a \)
$9-3a=7a+3$
$9-3=7a+3a$
$10a=6$
$a=\frac{6}{10}$
$a=\frac{3}{5}$
The value of $a$ is $\frac{3}{5}$.
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