Find the value of $36x^2 +49y^2-84xy$ if $x=2, y=-2$.

To do:

We have to find the value of $36x^2 +49y^2-84xy$ if $x=2, y=-2$.

Solution:

We know that,

$(a-b)^2=a^2-2ab+b^2$

Therefore,

$36x^2 +49y^2-84xy=(6x)^2-2\times6x \times7y+(7y)^2$

$=(6x-7y)^2$

$=(6\times2-7\times-2)^2$

$=(12+14)^2$

$=(26)^2$

$=676$

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Updated on: 10-Oct-2022

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