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Find the value of $ 1 \frac{1}{4}+3 \frac{1}{2} $.
Given:
\( 1 \frac{1}{4}+3 \frac{1}{2} \).
To do:
We have to find the value of \( 1 \frac{1}{4}+3 \frac{1}{2} \).
Solution:
$1\frac{1}{4}+3\frac{1}{2}=\frac{1\times4+1}{4}+\frac{3\times2+1}{2}$
$=\frac{4+1}{4}+\frac{6+1}{2}$
$=\frac{5}{4}+\frac{7}{2}$
$=\frac{5+7\times2}{4}$ (LCM of 2 and 4 is 4)
$=\frac{5+14}{4}$
$=\frac{19}{4}$
Therefore,
$1\frac{1}{4}+3\frac{1}{2}=\frac{19}{4}$.
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