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Find the total two-digit numbers which are divisible by $5$.
Given: Total two-digit numbers.
To do: To find the total two-digit numbers which are divisible by $5$.
Solution:
$10,\ 15,\ .....,\ 95$
As it is in A.P
First term, $a = 10$
Common difference, $d = 5$
Last term, $l = 95$
$l= a + (n-1)d = 95$
$\Rightarrow 10 + (n-1)5 = 95$
$\Rightarrow (n-1) = \frac{( 95-10)}{5} = \frac{85}{5} = 17$
$\Rightarrow n - 1 = 17$
$\Rightarrow n = 17+1 = 18$
There are $18$ terms of two digit numbers that are divisible by $5$.
Updated on: 10-Oct-2022
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