Find the total surface area of a right circular cone with radius $6\ cm$ and height $8\ cm$.

 Given:

The radius of a right circular cone is $6\ cm$ and height is $8\ cm$.

To do:

We have to find the total surface area of the right circular cone.

Solution:

Radius of the base of the cone $(r) = 6\ cm$

Height of the cone $(h) = 8\ cm$

Slant height of the cone $(l)=\sqrt{r^{2}+h^{2}}$

$=\sqrt{(6)^{2}+(8)^{2}}$

$=\sqrt{36+64}$

$=\sqrt{100}$

$=10 \mathrm{~cm}$

The total surface area of the cone $=\pi r(l+r)$

$=\frac{22}{7} \times 6(10+6)$

$=\frac{22 \times 6 \times 16}{7}$

$=\frac{2112}{7}$

$=301.71 \mathrm{~cm}^{2}$

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Updated on: 10-Oct-2022

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