Find the surface area of a sphere of radius
(i) $ 10.5 \mathrm{~cm} $
(ii) $ 5.6 \mathrm{~cm} $
(iii) $ 14 \mathrm{~cm} $.
To do:
We have to find the surface area of the given spheres.
Solution:
(i) Radius of the sphere $(r) = 10.5\ cm$
Therefore,
Surface area of the sphere $= 4\pi r^2$
$=4 \times \frac{22}{7}(10.5)^{2}$
$=4 \times \frac{22}{7} \times \frac{21}{2} \times \frac{21}{2}$
$=1386 \mathrm{~cm}^{2}$
(ii) Radius of the sphere $(r)=5.6 \mathrm{~cm}$
Therefore,
Surface area of the sphere $=4 \pi r^{2}$
$=4 \times \frac{22}{7} \times(5.6)^{2}$
$=4 \times \frac{22}{7} \times \frac{56}{10} \times \frac{56}{10}$
$=\frac{39424}{100}$
$=394.24 \mathrm{~cm}^{2}$
(iii) Radius of the sphere $(r)=14 \mathrm{~cm}$
Therefore,
Surface area of the sphere $=4 \pi r^{2}$
$=4 \times \frac{22}{7} \times(14)^{2}$
$=4 \times \frac{22}{7} \times 14 \times 14$
$=2464 \mathrm{~cm}^{2}$
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