Find the sum:$-5+\frac{7}{10}+\frac{3}{7}+(-3)+\frac{5}{14}+\frac{4}{5}$"

Given: $-5+\frac{7}{10}+\frac{3}{7}+(-3)+\frac{5}{14}+\frac{4}{5}$

To do: To find the sum $-5+\frac{7}{10}+\frac{3}{7}+(-3)+\frac{5}{14}+\frac{4}{5}$.

Solution:

$-5+\frac{7}{10}+\frac{3}{7}+(-3)+\frac{5}{14}+\frac{4}{5}$

$=-5-3+( \frac{7}{10}+\frac{3}{7}+\frac{5}{14}+\frac{4}{5})$

$=-8+( \frac{7\times7}{70}+\frac{3\times10}{70}+\frac{5\times5}{70}+\frac{4\times14}{70})$

$=-8+( \frac{49+30+25+56}{70})$

$=-8+\frac{160}{70}$

$=\frac{16}{7}-8$

$=\frac{16-56}{7}$

$=-\frac{40}{7}$

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Updated on: 10-Oct-2022

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