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Find the sum of first five multiples of $3$.
Given: First five multiples of $3$.
To do: To find the sum of first five multiples of $3$.
Solution:
First five multiples of $3$ are: $3,\ 6,\ 9,\ 12,\ 15$
$a=3,\ d=3,\ n=5$
Sum of an AP is:
$\frac{n}{2}\times ( 2a+( n−1)d)$
Sum $=\frac{5}{2}\times ( 2\times 3+( 5−1)\times ( 3))$
$=\frac{5}{2}\times ( 6+12)$
$=45$
Thus, sum of the first five multiples of $3$ is $45$.
Updated on: 10-Oct-2022
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