Find the side of a cube whose volume is $\frac{729}{343} cm^3$

Given :

The volume of the cube is $\frac{729}{343} cm^3$

To do :

We have to find the side of the cube.

Solution :

The volume of a cube of side 'a' $=a^3$

So, $a^3 = \frac{729}{343} cm^3$

$a = \sqrt[3]{\frac{729}{343} cm^3}$

$a = \sqrt[3]{\frac{9 \times 9 \times 9}{7 \times 7 \times 7} cm^3}$

$a =  \sqrt[3]{\frac{9^3}{7^3} cm^3}$

We know that, $\sqrt[3]{x^3} = x$

Therefore, $a = \frac{9}{7} cm$.

Side of the cube is $ \frac{9}{7} cm$.

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Updated on: 10-Oct-2022

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