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Find the ratio of the curved surface areas of two cones if their diameters of the bases are equal and slant heights are in the ratio $4 : 3$.
Given:
The diameters of the bases of two cones are equal and slant heights are in the ratio $4 : 3$.
To do:
We have to find the ratio of the curved surface areas of the cones.
Solution:
Let the diameters of each cone be $d$.
This implies,
Radius of each cone $(r) =\frac{d}{2}$
Ratio of the slant heights $= 4 : 3$
Let the slant height of the first cone be $4x$ and the slant height of the second cone be $3x$.
Therefore,
Curved surface area of the first cone $= 2 \pi rh$
$=2 \times \pi \times \frac{d}{2} \times 4 x$
$=4 \pi d x$
Curved surface area of the second cone $=2 \times \pi \times \frac{d}{2} \times 3 x$
$=3 \pi d x$
Ratio of the curved surfaces of the cones $=4 \pi d x: 3 \pi d x$
$=4: 3$
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