Find the product by suitable rearrangement:
(a) $ 2 \times 1768 \times 50 $
(b) $ 625 \times 279 \times 16 $

Given:

(a) \( 2 \times 1768 \times 50 \)
(b) \( 625 \times 279 \times 16 \)

To do: 

Here we have to find the value of the given expressions by suitable rearrangement.

Solution:

(a) Rearrangement is done to make calculations easy.

In this case, it is difficult to calculate the product of 2 and 1768 and then again multiply that value with 50 to get the final answer.

$2\ \times\ 1768\ \times 50$

Now, we know that product of 2 and 50 is easy to calculate. So, rearranging the digits:

$=\ 1768\ \times\ (2\ \times\ 50)$

$=\ 1768\ \times \ 100$

It is easier to calculate the final value now:

$=\ \mathbf{176800}$

So, the value of the given expression is 176800. 

(b) Rearrangement is done to make calculations easy.

In this case, it is difficult to calculate the product of 625 and 279 and then again multiply that value with 16 to get the final answer.

$625\ \times\ 279\ \times 16$

Now, we know that product of 625 and 16 is easy to calculate. So, rearranging the digits:

$=\ 279\ \times\ (625\ \times\ 16)$

$=\ 279\ \times \ 10000$

It is easier to calculate the final value now:

$=\ \mathbf{2790000}$

So, the value of the given expression is 2790000. 

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Updated on: 10-Oct-2022

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