Find the perimeter of the rectangle given below and then, find its value for $ x=1, \mathrm{y}=2 $."

To do:

We have to find the perimeter of the given rectangle and find its value for \( x=1, \mathrm{y}=2 \).
Solution:

We know that,

Perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$.

Therefore,

Perimeter of the given rectangle $=2[(5x-y)+2(x+y)]$
$=2(5x-y+2x+2y)$

$=2(7x+y)$

$=2(7x)+2(y)$

$=14x+2y$

The perimeter of the rectangle for \( x=1, \mathrm{y}=2 \) is,

Perimeter $=14(1)+2(2)$

$=14+4$

$=18$.

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Updated on: 10-Oct-2022

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